1. Find the least value of m such that log(m^2 – 15m) to base 10 is 2 ?
1. Answer:-5
Solution:From the given equation, we have m^2 – 15m = 10^2 = 100. This can be written as (m + 5) (m – 20) = 0 and so m = -5, 20. The least value of m is clearly -5.
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